Question

find the work done by force f=2i+3j+k in moving an object through a displacement [i^+j^+k^]m

Answer 1

Answer:

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Explanation:

Work = F .r where F and r are vectors,

F = 2i+3j+k

r = 1i+2j-4k

F.r = (2)(1) +(3)(2) + (1)(-4)

=2 +6 -4 =4

Hence work done is 4 units.

The important thing here is the knowledge of dot product.

i.i = j.j=k.k =1

i.j=j.k=k.i=0