Find the work done by some external force in moving a charge q=2muC from infinity to a point where electric potential is 10^4 V.
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Answer: work done will be .02 Joule
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Given that a charge q = 2 × 10^-6 C is brought from infinity to a point where the potential (V) is equal to 10⁴ V.
We have to find the work done to move this charge .The work done will be equal to the product of charge and the potential difference.
Work done = charge × potential
= qV
= 2 × 10^-6 × 10⁴
= 0.02 J
The work done by the external force = 0.02 J
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