find the work done if time is 3,5 and the s=(4t^3+5t^4+5t) and mass of the body is 4 kg
Answers
Answered by
1
Answer:
Given Mass m=4kg
Force
F
=(4
i
^
+12t
2
j
^
)N
Initial velocity
v
=(2
i
^
+
j
^
+2
k
^
)m/s
Magnitude of
v
=
2
2
+I
2
+I
2
=
9
=3m/s
Net force =
∣
∣
∣
∣
(4i+
∣
∣
∣
∣
2t
2
j
^
∣
∣
∣
∣
)N
∣
∣
∣
∣
⇒ma=
16
2
+144t
4
⇒4a=4
1+9t
4
⇒a=
1+9t
4
⇒
dt
dv
=
1+9t
4
⇒v=
1
2
+(3t
2
)
2
at(t=1)=4
Work = Force × displacement
=12.6×
3
1
=4J
Similar questions