find the work done to carry a charge 3.2 x 10^-19 C from 5v to +20 V
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Explanation:
We know that potential difference = Work done/Charge moved.
In this case, V = 230 V and V2 = 240 V. The mount off charge moved = 5 C.
Thus, the potential difference = v2-V1 = 230-240 = 10 V
Therefore, Work done = Potential difference * Charge moved.
That is, 10 * 5 = 50 Joules.
Hence, the work done in moving a charge of 5 coulombs from a point at 230 volts to another point at 240 volts is 50
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