Question

find the workdone required to raise on object of mass 6kg to a height of 15m and then bring down to the height of 5m. Also find the net workdone?​

Answer 1

Answer:

WORK DONE- MGH

6×10×15= 900 J

2 case

same as one

6×10×5

=300J

net work done

= 900+300= 1200/2

600J

Answer 2

Answer:

The work done to raise an object is given by the formula Work = Force x Distance x cos(theta), where force is the weight of the thing (mass x acceleration due to gravity), distance is the height the object is raised, and theta is the angle between the force and the displacement.

Explanation:

In this case, the force is the object's weight, which is 6 kg x 9.8 m/s^2 = 58.8 N.

The work done to raise the object to a height of 15m is:

Work = 58.8 N x 15 m x cos(90) = 882 J (Work is done upward)

The work done to bring the object back down to a height of 5m is:

Work = 58.8 N x 10 m x cos(0) = 588 J (Work is done downward)

Net work done is the algebraic sum of work done on an object. Since the job done in the first action is upward and the work done in the second action is downward, the net work done on an object will be the difference between those two works.

Net workdone = 882 J - 588 J = 294 J

So the work done to raise the object to a height of 15m is 882 J and to bring it back down to a height of 5m is 588 J. The net work done on the object is 294 J.

To learn more about Work = Force x Distance x cos(theta), from the given link.

https://brainly.in/question/15159612

To learn more about gravity, from the given link.

https://brainly.in/question/1258339

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