Question

Rationalise the denominator 6 − 4√36 − 4√3​

Answer 1

According to your given equation,

$6 - 4 \sqrt{36 } - 4 \sqrt{3} \\ 6 - 4 \times 6 - 4 \sqrt{3} \\ 6 - 24 - 4 \sqrt{3} \\ - 18 - 4 \sqrt{3}$

It is already in rationalized form

Answer 2

$\frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} }$

$\frac{6 - 4 \sqrt{3} }{6 + 4 \sqrt{3} } \times \frac{6 - 4 \sqrt{3} }{6 - 4 \sqrt{3} }$

$\frac{ ({6 - 4 \sqrt{3} })^{2} }{(6 + 4 \sqrt{3})(6 - 4 \sqrt{3} )}$

$\frac{36 - 48 \sqrt{3} + 48}{36 - 48}$

$\frac{84 - 48 \sqrt{3} }{ - 12}$

$- ( 7 - 4 \sqrt{3} )$

$\sf\green{{4 \sqrt{3} - 7}}$

#NAWABZAADI