Question

Find the wrong
$0 \div 0 = (9 - 9) \div (9 - 9) \\ = (3 {}^{2} - 3 {}^{2} ) \div (3 {}^{2} - 3 {}^{2} ) \\ = (3 + 3)(3 - 3) \div 3(3 - 3) \\ = (3 + 3) \div 3 = 6 \div 3 = 2$
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Answer 1

☆*:.｡.o(≧▽≦)o.｡.:*☆

♪H♪E♪Y♪ ♪M♪A♪T♪E♪ ♪H♪E♪R♪E♪ ♪I♪S♪ ♪Y♪O♪U♪ ♪A♪N♪S♪W♪E♪R♪

(3 - 3) will not get cancelled as only non zero numbers can be cancelled.

⚡H⚡O⚡P⚡E⚡ ⚡I⚡T⚡ ⚡W⚡I⚡L⚡L⚡ ⚡H⚡E⚡L⚡P⚡ ⚡Y⚡O⚡U⚡

☾F☽☾O☽☾L☽☾L☽☾O☽☾W☽ ☾F☽☾O☽☾R☽ ☾M☽☾O☽☾R☽☾E☽ ☾A☽☾N☽☾S☽☾W☽☾E☽☾R☽☾S☽

(◕‿◕)♡

Answer 2

Answer:

The "(3–3)" if taken common is not written..its to confuse everyone lol..

The correct goes like this.:---

$0 \div 0$

$(9 - 9)(9 - 9)$

$(3 ^{2} - {3}^{2} ) \div 3(3 - 3)$

$(3 + 3)(3 - 3) \div (3 - 3)3$

$(3 - 3)((3 + 3) \div 3)$

$(3 - 3)(6 \div 3)$

$(3 - 3)(2)$

$(0)(2)$

$= 0$