Find the x & y
plzz explain step by step
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Answer:
angle y = 45° [diagonals bisect the angles in a square]
therefore angle SQR=45°
Let the centre be O
and the angle 60° point be T
In ∆OQT
60°+45°+angle QOT=180°[A.S.P]
Angle QOT = 180-105 = 75°
x+75°=180°[st. line]
x=105°
therefore
x=105°
y=45°
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