Question

Find the x and y component of a 400N force at an angle of 125 to x-axis

Answer 1

Answer:

This is the standard problem of the translation of polar coordinates (r, \varphi) = (400, 125 \degree)(r,φ)=(400,125°) to rectangular (x,y)(x,y). The relationship is

x = r \cos \varphi = 400 \cos 125 \degree \approx -229.43, \\ y = r \sin \varphi = 400 \sin125 \degree \approx 327.66.x=rcosφ=400cos125°≈−229.43,

y=rsinφ=400sin125°≈327.66.

Answer 2

This is the standard problem of the translation of polar coordinates (r, \varphi) = (400, 125 \degree)(r,φ)=(400,125°) to rectangular (x,y)(x,y). The relationship is

x = r \cos \varphi = 400 \cos 125 \degree \approx -229.43, \\ y = r \sin \varphi = 400 \sin125 \degree \approx 327.66.x=rcosφ=400cos125°≈−229.43,

y=rsinφ=400sin125°≈327.66.

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