Question

Find the x Of the Following Y=2x+7° Z=45° X=?​

Answer 1

Step-by-step explanation:

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=OD

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50 ∘

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50 ∘ −50

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50 ∘ −50 ∘

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50 ∘ −50 ∘ =80

ABCD is a rectangle. We know that the diagonals of the rectangle are equal and bisect each other.⟹BD=AC and AO=BO=OC=ODIn △ABO,∠OAB=∠OBA=50 ∘ ---Angles opposite to the equal sides in a triangle are equal.In △AOB,∠AOB+∠OAB+∠OBA=180 ∘ ---sum of interior angles of a triangle∴∠AOB=x=180 ∘ −50 ∘ −50 ∘ =80 ∘

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