Question

Find the x+y+z

Answer the question ​

Answer 1

Step-by-step explanation:

ok let me explain you

given,

$<$PAR =x

< BAC=90 degree

<ABC = 30 degree

<ABQ = z

< BCR =Y

pab is a line

<PAR+ <BAC =180 DEGREE ( linear pair)

x= 90 degree = 180 degree

x= 180-90

x= 90

QBC is a line

<ABQ +<ABC = 180 (linear pair)

z+ 30 = 180

z= 180-30

z=150 degree

sorry  i forgot to mention

y= 120 degree

now,

x+y+z

so,

90 + 120+ 150= 360

so,

x+ y+z = 360 degree

hope it helps

over and happy to help:)

Answer 2

Answer:

z=180°-30° ---(Angles on straight line)

z=150°

Angle 1=30°

Angle 2=90°

Let Angle 3=A°

Therefore,we can,find angle 3 by,

angle 1+angle 2+angle 3=180°

30°+90°+A°=180°

A°=180°-120°

A°=60°

y=180°-60° ---(Angles on straight line)

y=120°

x°=180-90° ---(Angles on straight line)

x°=90°