find the zeores of the polynomial x^2-3 and verify the relationship between the zeores and the coefficient
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Step-by-step explanation:
x² - 3 = 0
x² = 3
x = + √3 or x = - √3
Since 'x' 's coefficient is 0
sum of roots is zero..
a + b = 0
√3 - √3 = 0
Here coefficient of constant term is -3
a × b = -3
√3 × (-√3) = -3
-3 = -3
Verified........
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