Question

find the zereos of the polynomial for l(x)=x^2+2+1
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Answer 1

P(x)=(x−2)

2

−(x−2)

2

This is in the form of a

2

−b

2

P(x)=(x−2+x+2)(x−2−(x+2))

P(x)=2x(x−2−x−2)

P(x)=2x(−4)

P(x)=0

−8x=0

x=0

Answer 2

Answer:

l(X)=x²+2+1

=x²+2+1=0

=x²+3=0

=x²=-3

=x=root over of -3......

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