Question

find the zero of a(x²+1)-x(a²+1)​

Answer 1

$a( {x}^{2} + 1) - x( {a}^{2} + 1) = 0 \\ (a {x}^{2} + a )-( x {a}^{2} + x) = 0 \\ a {x}^{2} - x {a}^{2} - x + a = 0 \\ ax(x - a) - 1(x - a) = 0 \\ (ax - 1)(x - a )= 0$

therefore,

$ax - 1 = 0 \\ ax = 1 \\ x = \frac{1}{a}$

or

$x - a = 0 \\ x = a$

hope it helps....

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