Question

find the zero of each of the following polynomials p(a)=(a-2)^2-(a+2)^2 ​

Answer 1

Answer:

Answer is above mentioned in the image

Step-by-step explanation:

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Answer 2

Answer :-

$x - 1 = 0 \\ x = 0 + 1 \\ x = 1 \\ \\ p(a) = {(a - 2)}^{2} - {(a + 2)}^{2} \\ p(1) = {(1 - 2)}^{2} - {(1 + 2)}^{2} \\ p(1) = { - 1}^{2} - {3}^{2} \\ p(1) = 1 + 9 \\ p(1) = 10$

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