Question

Find the zero of following
quadratic polynomial and verify the relationship ?
(i) x² = 2x - 8
(ii) 4s² - 4s + 1
(iii) 6x² - 3 - 7x = 0
(iv) 4u² + 8u
(vi) 3x² -x - 4 = 0
(v) t² - 15


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Answer 1

Step-by-step explanation:

X2=2x-8

X2-2x+8=0

X2-4x+2x+8=0 ml

x(x-4)+2(x-4)=0

(x+2)(x-4)=0

So, x=-2,x=4

so, -2and 4 are zeros of the polynomial.

2.

Answer 2

Answer:

Hi maroofa di

Sorry for spaming.

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