Math, asked by hridhyasree2004, 11 months ago

find the zero of op(x)= x²-8​

Answers

Answered by omsamarth4315
1

Answer:

zero =q

x²-8 = 0

x² = 8

x= +2root 2 and - 2root 2......

Answered by JayaramJR07
3

Answer:

Here is your answer mate

Step-by-step explanation:

Zero of p(X) = x^2 - 8

0=x^2-8

X^2 = 8

X = (8)^1/2

x =  \sqrt{8}

x =  \sqrt{ {2}^{2}  \times 2}

x = 2 \sqrt{2}

Hope it may help you

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