find the zero of polynomial 4✓3x²+5x-2√3 and verify its relationship between zeros and coefficient
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4√3 x^2 + 5x -2√3 (splitting the middle term)
=4√3 x^2 +(8-3)x -2√3
=4√3(√3x+2)-√3(√3x+2)
= (√3x+2) (4x-3)
x = -2/√3x = √3/4
So, alpha + beta = -b/a
= -5/4√3
Sum of zeros = -2/√3 + √3/4 = -5/4√3
Alpha×beta = c/a
= -2√3/4√3
= -1/2
Product of zeros = -2/√3 × √3/4
= -2√3/4√3
= -1/2
hence verified
=4√3 x^2 +(8-3)x -2√3
=4√3(√3x+2)-√3(√3x+2)
= (√3x+2) (4x-3)
x = -2/√3x = √3/4
So, alpha + beta = -b/a
= -5/4√3
Sum of zeros = -2/√3 + √3/4 = -5/4√3
Alpha×beta = c/a
= -2√3/4√3
= -1/2
Product of zeros = -2/√3 × √3/4
= -2√3/4√3
= -1/2
hence verified
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