find the zero of polynomial f(x)=x^2-2x-8
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Hey Friend !
f(x)=x² -2x - 8
x²- 4x + 2x - 8
= x [ x - 4 ] + 2 [ x - 4 ]
= [ x + 2 ] [ x - 4 ]
Hence ,
zeroes are :
- 2 and 4
f(x)=x² -2x - 8
x²- 4x + 2x - 8
= x [ x - 4 ] + 2 [ x - 4 ]
= [ x + 2 ] [ x - 4 ]
Hence ,
zeroes are :
- 2 and 4
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