hii plzz help me to do these questions....plzz sololve it... I will also Ur ans as brainelist plzz do only 3 and 4.
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isha321:
Sorry but I'm not in 9th so that's why cannot answer
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this is ur answer and u can do 3 with rationalising all the terms and then simply adding them.
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1/(3-√8) - 1/(√8-√7)+1/(√7-√6)-1/(√6-√5)+1/(√5-2)
By rationalising each of them we get
1/(3-√8)=3+√8
1/(√8-√7)=√8+√7
1/(√7-√6)=√7+√6
1/(√6-√5)=√6+√5
1/(√5-2)=√5+2
1/(3-√8) - 1/(√8-√7)+1/(√7-√6)-1/(√6-√5)+1/(√5-2)=3+√8-(√8+√7)+√7+√6-(√6+√5)+√5+2
=3+√8-√8-√7+√7+√6-√6-√5+√5+2
=5
Here I had to change the sign before 1/(√6-√5) into - as it wasn't possible for me to get the answer keeping the sign+
By rationalising each of them we get
1/(3-√8)=3+√8
1/(√8-√7)=√8+√7
1/(√7-√6)=√7+√6
1/(√6-√5)=√6+√5
1/(√5-2)=√5+2
1/(3-√8) - 1/(√8-√7)+1/(√7-√6)-1/(√6-√5)+1/(√5-2)=3+√8-(√8+√7)+√7+√6-(√6+√5)+√5+2
=3+√8-√8-√7+√7+√6-√6-√5+√5+2
=5
Here I had to change the sign before 1/(√6-√5) into - as it wasn't possible for me to get the answer keeping the sign+
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