find the zero of polynomial in the following case
1. (x+1)(x+2)
Answers
Answered by
2
Step-by-step explanation:
(x+1)(x+2)
(x+1)=0. (x+2)=0
x=-1. x=-2
So the zeroes are -1 and -2
Answered by
1
Answer:
Zeros are -1 and -2
Step-by-step explanation:
(x+1)(x+2)
x+1=0,x+2=0
x=-1 ,x=-2
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