find the zero of polynomial the sum and product of whose zeroes are -3 and 2
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1
alpha + beta = -3
alpha and beta =2
using k (x^2-(alpha + beta ) + alpha × beta)
x^2+3x+2
alpha and beta =2
using k (x^2-(alpha + beta ) + alpha × beta)
x^2+3x+2
Answered by
2
Let Zeroes be a and b respectively
we have, a+b = -3 and ab = 2
We know that quadratic polynomial is x² - (a+b)x + ab
Hence required polynomial = x² -(-3)x + 2 = x² + 3x + 2
we have, a+b = -3 and ab = 2
We know that quadratic polynomial is x² - (a+b)x + ab
Hence required polynomial = x² -(-3)x + 2 = x² + 3x + 2
varun26mehrotra:
thank you
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