Find the zero of polynomial X² + ax + 3
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Answer:
Correct option is
A
9
It is given that 3 is a zero of the polynomial p(x)=3x
3
−x
2
−ax−45 which means that p(3)=0, so let us substitute x=3 in p(x) to find the value of a as shown below:
p(3)=3(3)
3
−(3)
2
−a(3)−45
⇒0=(3×27)−9−3a−45
⇒0=81−9−3a−45
⇒0=81−54−3a
⇒0=27−3a
⇒3a=27
⇒a=
3
27
⇒a=9
hence, a=9.
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