Question

find the zero of quadratic poly nominal(X2+5) verify the relation between the zero and cofficient​

Answer 1

$polynomial \: \: = {x}^{2} + 5$

$zero \: be \: \alpha \: \beta .( \alpha >\beta )$

${x}^{2} + 5 = 0 \: ,\: \: {x}^{2} = - 5 \: \: , \: \: \: \: x = ± \sqrt{5}$

$\alpha = \sqrt{5} \: , \: \: \beta = - \sqrt{5}$

$so \: , \alpha + \beta = 0 ,\: \: \alpha \beta = - 5$

$coefficient \: \: = \: \alpha + \beta = 0$