Question

find the zero of quadratic polynomial 6x2-3-7x
​

Answer 1

Answer:

the zero is

Step-by-step explanation:

6x2-7x-3

6x2-9x+2x-3

3x(2x-3)+1(2x-3)

therefore the zeros are

-1/3,3/2

Answer 2

$\huge \rm \underline \red{question}$

Actually , the correct sequence of ur equation will be 6x² - 7x - 3

$\huge \rm \underline \purple{answer}$

By splitting method :

$\rm \longrightarrow \: 6x {}^{2} - 9x + 2x - 3$

$\rm \longrightarrow \: 3x(2x - 3) \: + 1(2x - 3)$

$\rm \longrightarrow \: (2x - 3)(3x + 1)$

$\rm \longrightarrow \: x = \frac{3}{2}$

$\rm \longrightarrow \: x = \frac{ - 1}{3}$