find the zero of quadratic polynomial x^2 - 4 x + 3
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Answered by
1
Answer:
x square -4x +3=0
multiply the coefficient of a and c we get
1*3=3
so then factorize
x square x+3x+3=0
x(x+1) +3(x+1)=0
(x+1)(x+3)=0
x=-1,-3
zeroes are x+1 and x+3
Step-by-step explanation:
vineet6981:
I can't understand this question
hi vineet is there any problem with my answer you are free to say so and i will rectify my mistake.
okkk
i only have used the word square instead of^ please tell me why have you reported my answer
there was - 4x you have made the factors of plus 4x that's why I reported your answer
okkk
have you remember your mistake or not
oh ok my bad sorry
Answered by
0
Step-by-step explanation:
✓ x^2-4x+3=0
✓ x^2-x-3x+3=0
✓ x(x-1)-3(x-1)=0
✓ (x-3)(x-1)=0
So, when (x-3) is equated to zero, x=3
and, when (x-1) is equated to zero, x=1
That is: Zeroes of given polynomial are 3 and 1.
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