Question

find the zero of quadratic polynomial X2 + 99 X + 127

Answer 1

Product of zeroes of ax2+ bx + c = c/a
Product of the zeroes of x2+ 99x + 127 = 127

Sol:
The product of zeroes is positive. So either 'both zeroes are positive' or 'both zeroes are negative'.
The zeroes are not equal as discriminant of x2+ 99x + 127 = Ö[992 – 4(127)] is not equal to zero.

Also, the sum of the zeroes is –99 (sum of zeroes of ax2+ bx + c = –b/a)

The sum of zeroes is negative and the product of the zeroes is positive.

So we can conclude that 'both the zeroes of the polynomial are negative'.