Find the zero of the following quadratic polynomials
• P(x) = 6x² = 3-7x and verify the relationship between the
Zeros and the co-efficient
Answers
Answered by
2
6x
2
−3−7x=6x
2
−7x−3=0
⇒6x
2
+2x−9x−3=0
⇒2x(3x+1)−3(3x+1)=0
⇒(2x−3)(3x+1)=0
Zeros =
2
3
,
3
−1
α+β=
a
−b
⇒
2
3
−
3
1
=
6
7
=
6
(−7)
=
a
−b
αβ=
a
c
⇒(
2
3
)(
3
−1
)=
2
−1
=
6
−3
=
a
c
Hence proved.
2
−3−7x=6x
2
−7x−3=0
⇒6x
2
+2x−9x−3=0
⇒2x(3x+1)−3(3x+1)=0
⇒(2x−3)(3x+1)=0
Zeros =
2
3
,
3
−1
α+β=
a
−b
⇒
2
3
−
3
1
=
6
7
=
6
(−7)
=
a
−b
αβ=
a
c
⇒(
2
3
)(
3
−1
)=
2
−1
=
6
−3
=
a
c
Hence proved.
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