Question

Find the zero of the polynomia f(x) = px + q, p ≠ 0, p q are real numbers

*answer step wise pls*

Answer 1

Answer:

f(x) = p(X) + q

f(0) = p(0) +0

= 0+0

= 0

f(x) = p(1) + 1

= 1+1

= 2

Answer 2

Answer:

$\frac{ - q}{p}$

Step-by-step explanation:

Given:-

f(x) = px + q, p ≠ 0, p q are real numbers

To find:-

zero of the polynomial px+q

Approach:-

zero of polynomial f(x) means the value of x

let,

$\: \: \: \: \: \: \: \: \: \: \: \: px + q = 0$

$\longrightarrow \: px = - q$

$\longrightarrow \: x = \frac{ - q}{p}$

Final answer:-

-q/p

Thank you!