Find the zero of the polynomial (2x+1)( 3x-4)
Answers
Answered by
1
✔✔heya here is ur answer!!!
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☆ (2x+1) = 0
=> 2x = -1
=> x = -1/2
☆ (3x-4) = 0
=> 3x = 4
=> x = 4/3
THANK YOU ✌✌
HOPE IT HELPS YOU ☺☺
___________________________
☆ (2x+1) = 0
=> 2x = -1
=> x = -1/2
☆ (3x-4) = 0
=> 3x = 4
=> x = 4/3
THANK YOU ✌✌
HOPE IT HELPS YOU ☺☺
Answered by
1
Given, (2x+1)(3x-4)
Now, = 6x²-8x+3x-4
= 6x²-5x-4
= 6x²-(3-8)x-4
= 6x²-3x+8x-4
= 3x(2x-1)+4(2x-1)
=> (3x+4)=0 and (2x-1)=0
3x+4=0 and 2x-1=0
x= -4/3. and. x=1/2
So, we neglect the negative term and the zero of the polynomial is x=1/2
Now, = 6x²-8x+3x-4
= 6x²-5x-4
= 6x²-(3-8)x-4
= 6x²-3x+8x-4
= 3x(2x-1)+4(2x-1)
=> (3x+4)=0 and (2x-1)=0
3x+4=0 and 2x-1=0
x= -4/3. and. x=1/2
So, we neglect the negative term and the zero of the polynomial is x=1/2
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