Question

find the zero of the polynomial 3x²/2=3​

Answer 1

Answer:

$\sqrt{2} , -\sqrt{2}$

Step-by-step explanation:

$\frac{3x^{2} }{2} =3$

$3x^{2} = 3*2$

$3x^{2} =6$

$3x^{2} -6=0$

$3(x^{2}-2)=0$

$x^{2}-2=0$

$x^{2} -(\sqrt{2} )^{2} =0$     ----- use the formula $a^{2} -b^{2} =(a+b)(a-b)$

$(x+\sqrt{2} )(x-\sqrt{2} )=0$

$(x+\sqrt{2} )=0 \\(x-\sqrt{2} )=0$

$x = \sqrt{2}$

or

$x = -\sqrt{2}$