Question

find the zero of the polynomial ​

Answer 1

Answer:

1, 3/2 and -4/3

Step-by-step explanation:

$6x^3-7x^2-11x+12 \\ \\ 6x^3-6x^2-x^2+x-12x+12 \\ \\ 6x^2(x-1)-x(x-1)-12(x-1) \\ \\ (x-1)(6x^2-x-12) \\ \\ (x-1)(6x^2+8x-9x-12) \\ \\ (x-1)(2x(3x+4)-3(3x+4)) \\ \\ (x-1)(2x-3)(3x+4)$

So the zeros are 1, 3/2 and -4/3.

Thank you...