find the zero of the polynomial and verify the relationship between zero and coefficient i) 8x²–18x–5
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Answered by
6
this is simple...
8 is the coefficient of x squared
-18 is the coefficient of x
-5 is the constant
now solve it...
axsquared + bx + c
so the zeroes are b/ a
and -c/a
Answered by
6
8x^2-18x-5=0
8x^2-20x+2x-5=0
4x(2x-5)+(2x-5)=0
x=5/2,-1/4
sum of the rootsis -18/8
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