Question

Find the zero of the polynomial given below:-

l(x)=x²+2x+1 ​

Answer 1

Answer:

-1

Step-by-step explanation:

=x²+2x+1

=x²+x+x+1

=x(x+1)+1(x+1)

=(x+1)(x+1)

x+1=0

⇒x= -1

∴zeroes of this polynomial are -1 and -1

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