Question

Find the zero of the polynomial in each of the following cases: (i) p(x) = x + 5 (ii) p(x) = x − 5 (iii) p(x) = 2x + 5 (iv) p(x) = 3x − 2 (v) p(x) = 3x (vi) p(x) = ax, a ≠ 0 (vii) p(x) = cx + d, c ≠ 0, c, are real numbers.

Answer 1

Step-by-step explanation:

I.-5

2.5

3.-5/2

4.2/3

5.0

6.0

7.-d/c

Answer 2

Hey Dear,

# Answers with calculation -

(i) p(x) = x + 5

To find zero of the polynomial,

p(x) = 0

x + 5 = 0

x = -5

(ii) p(x) = x − 5

To find zero of the polynomial,

p(x) = 0

x - 5 = 0

x = 5

(iii) p(x) = 2x + 5

To find zero of the polynomial,

p(x) = 0

2x + 5 = 0

2x = -5

x = -5/2

(iv) p(x) = 3x − 2

To find zero of the polynomial,

p(x) = 0

3x - 2 = 0

3x = 2

x = 2/3

(v) p(x) = 3x

To find zero of the polynomial,

p(x) = 0

3x = 0

x = 0/3

x = 0

(vi) p(x) = ax

To find zero of the polynomial,

p(x) = 0

ax = 0

x = 0/a

x = 0

(vii) p(x) = cx + d

To find zero of the polynomial,

p(x) = 0

cx + d = 0

cx = -d

x = -d/c

Thanks dear...