Question

find the zero of the polynomial in each of the following case
1)p(x)=(x+1)(x+2)
2)p(x)=x square - 3 x + 2 ​

Answer 1

Answer:

1. -1, -2

2. 1,2

Step-by-step explanation:

1. x+1=0. x+2=0

x=-1 x=-2

2. x square - x - 2x +2

x(x-1) - 2(x-1)

(x-1)(x-2)

x=1 , x=2

Answer 2

Step-by-step explanation:

1. p(x)= o

o= (x+1)(x+2)

either x+1=0. or x+2=0

x=-1 or x= -2

2. p(x)=0

${x}^{2} - 3x + 2 \\ (x - 2)(x - 1)$

either ( x-2)=0 or ( x-1)=0

x=2 or x=1