Question

Find the zero of the polynomial in each of the following cases : (i) p(x) = 2x - 3 (ii) p(y) = ay – b, a = 0 (iii) Q(x) = 4x + 3 (iv) q(t) = (t + 1)2 – (t - 1)2​

Answer 1

1) x= 3/2

2) y= 0

3) x= -3/4

4) 0

hope it will help you

Answer 2

Solution: (i)p(x) = x + 5

Plug p(x) = 0 we get

=>x+5 =0

=> x = - 5

-5 is zero of the polynomial

(ii) p(x) = x – 5

Plug p(x) = 0 we get

=>x - 5 = 0

=> x = 5

5 is zero of the polynomial

(iii) p(x) = 2x + 5

Plug p(x) = 0 we get

=>2x+5 =0

=> 2x = - 5

=> x= -5/2

-5/2is zero of the polynomial

(iv) p(x) = 3x – 2

Plug p(x) = 0 we get

=>3x-2=0

=>3x =2

=> x = 2/3

2/3 is zero of the polynomial

(v) p(x) = 3x

Plug p(x) = 0 we get

=>3x=0

=> x= 0/3

=> x=0

0 is zero of the polynomial

(vi) p(x) = ax, a ≠ 0

Plug p(x) = 0 we get

=>ax=0

=> x =0/a

=> x = 0

0 is zero of the polynomial

(vii) p(x) = cx + d, c ≠ 0, c, d are real numbers.

Plug p(x) = 0 we get

=>cx +d = 0

=> cx = - d

=> x = -d/c

-d/c is zero of the polynomial

hope it's correct and helps to you....