Question

find the zero of the polynomial in each of the following cases p(x)=(x+1)(x+2)​

Answer 1

Answer:

zeros are x=-1

x=-2

Step-by-step explanation:

p(x)=(x+1)(x+2)

=x(x+1)+2(x+1)

=x²+x+2x+1

=x²+3x+1

Answer 2

Answer:

in 1. (x+1) = x+1=0

then,

x= -1

And (x+2) =x+2=0

then x= -2

hence zeroes are -1 and -2

Step-by-step explanation:

hope it's help

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