Math, asked by atharvgupta30, 4 months ago

Find the zero of the polynomial of p(x) = ax+b, a and b are real numbers and c ≠ 0

Answers

Answered by Anonymous
5

Step-by-step explanation:

Here, p(x)=ax,a

Here, p(x)=ax,a

Here, p(x)=ax,a=0.

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,i.e p(x)=0.

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,i.e p(x)=0.⇒ax=0⇒x=0. (∵a

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,i.e p(x)=0.⇒ax=0⇒x=0. (∵a

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,i.e p(x)=0.⇒ax=0⇒x=0. (∵a=0)

Here, p(x)=ax,a=0.In order to find zero of p(x), we equate p(x) to 0,i.e p(x)=0.⇒ax=0⇒x=0. (∵a=0)∴ 0 is the zero of p(x).

Similar questions