find the zero of the polynomial of x²-5x+6
Answers
Answered by
317
to find zero of a quadratic equation , we have to factorize it ,
=> x²-5x+6 = 0
=> splitting the middle term,
=> x²-3x-2x+6 = 0
=> x(x-3)-2(x-3) = 0
=> (x-3)(x-2) = 0
x-3 = 0
=> x= 3
x-2 = 0
=> x = 2
hope this helps
=> x²-5x+6 = 0
=> splitting the middle term,
=> x²-3x-2x+6 = 0
=> x(x-3)-2(x-3) = 0
=> (x-3)(x-2) = 0
x-3 = 0
=> x= 3
x-2 = 0
=> x = 2
hope this helps
Answered by
158
hi friend
here your answer looking for
So, to get the zero of p(x) we know that,
p(x) = 0
p(x) = x^2 - 5x + 6
so,
x^2 -5x+ 6= 0
now , we factorise p(x) by splitting the middle term.
x^2-2x-3x+6=0
x(x-2)-3(x-2)=0
so,
(x-2)(x-3)=0
now, we get the value of x = 2 and 3.
So, 2 and 3 are the zeros of the polynomial x^2-5x+6.
hope it's helpful for you
for further help contact me
From brainly star Amaytripathi19
here your answer looking for
So, to get the zero of p(x) we know that,
p(x) = 0
p(x) = x^2 - 5x + 6
so,
x^2 -5x+ 6= 0
now , we factorise p(x) by splitting the middle term.
x^2-2x-3x+6=0
x(x-2)-3(x-2)=0
so,
(x-2)(x-3)=0
now, we get the value of x = 2 and 3.
So, 2 and 3 are the zeros of the polynomial x^2-5x+6.
hope it's helpful for you
for further help contact me
From brainly star Amaytripathi19
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