Question

Find the zero of the polynomial p(x)=2x²-5x-3

Answer 1

Given:

A polynomial $\[p(x) = 2{x^2} - 5x - 3\]$

To Find:

We have to find the zero of the given polynomial.

Solution:

To find zero of polynomial we have to put p(x) = 0.

$\[\begin{gathered} p(x) = 0 \hfill \\ 2{x^2} - 5x - 3 = 0 \hfill \\ 2{x^2} - 6x + x - 3 = 0 \hfill \\ 2x(x - 3) + 1(x - 3) = 0 \hfill \\ (x - 3)(2x + 1) = 0 \hfill \\ Either(x - 3) = 0or(2x + 1) = 0 \hfill \\ x = 3orx = ( - 1/2) \hfill \\ \end{gathered} \]$

Hence , x=3 and x= -1/2 are the two zeros of the given polynomial.

 

Answer 2

Answer:

6

Step-by-step explanation:

by putting x = -3

P(x) = 2x²+5x+3

=2(-3)²+5(-3)+3

=2×9+(-15)+3

=18-15+3

=3+3

=6