The sum of integers between. 1 abd 500 which are multiples of 2 as well as 5
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Clearly, the numbers between 1 and 500 which are multiples of 2 as well as of 5 i.e. which are multiples of 10 are 10,20,30,...,490.
This is an AP with first term a=10, common difference d=10 and last term l=490.
Let there be n terms in this AP. Then,
a
n
=490⇒a+(n−1)d=490⇒10+(n−1)×10=490
⇒(n−1)10=480⇒n−1=48⇒n=49
∴Required sum=S
n
=
2
n
[a+l]=
2
49
[10+490]=12250
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