Question

find the zero of the polynomial p(x) 4x^2-4x -3​

Answer 1

Answer:

x=-1/2 & x=3/2

Step-by-step explanation:

p(x)=4x^2-4x-3

=4x^2-6x+2x-3

=2x(2x-3)+1(2x-3)

=(2x+1)(2x-3)

x= -1/2 , x=3/2

plz mark as brainliest

Answer 2

⠀⠀⠀⠀⠀⠀⠀⠀☆ GIVEN POLYNOMIAL : p(x) = 4x² - 4x - 3 ⠀⠀⠀⠀

⠀⠀⠀⠀⠀⠀

$\qquad \dashrightarrow \sf \:\:4x^2 \:\:- \:\:4x\:\: -\:\: 3 \:\:=\:\: 0\:\: \\\\\qquad \dashrightarrow \sf \:\:4x^2 \:\:- \:\:6x\:\:+\:\:+2x\: -\:\: 3 \:\:=\:\: 0\:\: \\\\\qquad \dashrightarrow \sf \:\: 2x\:\:( \:\:2x\:\: - \:\:3\:\:) \:\:+ \:\:1 \:\:(\:\: 2x\:\: -\:\: 3\:\: )\:\:\: =\:\:0\: \: \\\\\qquad \dashrightarrow \sf \:\:( \:\:2x\:\: - \:\:3\:\:) \:\:+ \:\:1 \:\:(\:\: 2x\:\: +\:\: 1\:\: )\:\:\: =\:\:0\: \: \\\\\qquad \dashrightarrow \sf \:\:x\:\: = \:\:\dfrac{\:\:3\:\:}{\:\:2\:\:}\:\:or \:\:\:x\:\: = \:\:\dfrac{\:\:-1\:\:}{\:\:2\:\:}\:\:\: \: \\\\\qquad \therefore \:\:\underline {\boxed{\pmb{\purple{\frak{\:x\:= \: \dfrac{3}{2} \:\: or \: \dfrac{-1}{2} \:\:\: }}}}}\:\:\bigstar$

$\qquad \therefore \:\underline { \sf Hence, \: \:Zeroes \:of \:Quadratic \:are \: \bf 3/2 \:\: \sf and \:\bf -1/2 \:\:.}$

⠀⠀⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━⠀

¤ More To Know :

$\qquad \qquad \boxed {\begin{array}{cc} \bf{\underline {\bigstar\:\: For \: a \:Quadratic \:Polynomial \::}}\\\\ \sf{ Whose \:\:zeroes \:\:are\:\:\alpha \:\&\;\: \beta\:\:} \\\\ 1)\:\: \alpha + \beta \: =\:\dfrac{-b}{a} \quad \bigg\lgroup \bf Sum\:of\;Zeroes \bigg\rgroup \\\\ 2)\:\: \alpha \times \beta \: =\:\dfrac{c}{a} \quad \bigg\lgroup \bf Product \:of\;Zeroes \bigg\rgroup \\\\ \end{array}}$