Find the zero of the polynomial p(y) =q^3÷27-1
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Step-by-step explanation:
Hey.. mate ❤
Good morning dear
here ur answers step by step
y^3/27 - 1 = 0
=> ( y/3 )^3 - 1 = 0
=> ( y/3 )^3 = 1
=> y ^3 /27 = 1
=> y^3 = 27
=> y = plus minus 3
hope its helpful for you.....dear✌✌✌
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