find the zero of the polynomial quadratic polynomial and verify the relationship between the zeros and the coefficients x²-2x-8
Answers
Answered by
21
Answer:
x²-2x-8
Step-by-step explanation:
x²-4x+2x-8
x(x-4)+2(x-4)
(x+2) (x-4)
x=-2,x=4
i hope it helps you
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Answered by
5
Answer:
x²-2x-8
x²-4x+2x-8
x(x-4)+2(x-4)
(x-4)(x+2)
x-4=0 or x+2=0
x=4 or x= -2
therefore,4 and -2 are the zeroes of given polynomilal
relationship between zeroes and coefficients:
sum of zeroes= 4+(-2)=4 - 2 =2 = -(-2)/1 = -b/a
product of zeroes = 4×-2 = -8 = -8/1 =c/a
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