Question

Find the zero of the polynomial x^2-2 using factorization method

Answer 1

Step-by-step explanation:

x^2-2=0

a+b =0

ab = -2

a= +√2

b=-√2

x^2+√2x -√2x -2 =0

x(X+√2) -√2(X+√2) =0

(x-√2)(X+√2) =0

so the roots/zeroes are √2,-√2

please mark BRAINIEST

Answer 2

Answer:x^2-2=0

x^2-$-\sqrt{2)$^2=0

$(x+\sqrt{2)$$(x-\sqrt{2)$=0

x=$-\sqrt{2$  ;   x=$\sqrt{2$

plz mark as the brainliest

Step-by-step explanation: