Question

Find the zero of the polynomial (x-2)^+4

Answer 1

➡️ANSWER

we have ,

(x-2)^2 +4

= x^2 +4 - 4x + 4

= x^2 - 4x + 8

➡️for zeroes

x^2 - 4x + 8 = 0

such that , a = 1 , b = -4 & c = 8

➡️now, by quadratic formula for value of x

x = ( -4 ± √-4^2+4×8×1) / 2×1

=> x = ( -4 ± √48 ) / 2

=> x = (-4 ± 4√3) / 2

=> x = (-4 + 4√3 ) / 2 or. (-4 - 4√3) /3

=> x = -2(1-√3) or -2(1+√3)

【 HOPE IT HELP YOU 】

Answer 2

Step-by-step explanation:

(x-2)+4=0

(x-2)=-4

X=-4+2

X=-2

Hope it will help you