the perimeter of an isosceles triangle is 32 CM the ratio of the equal side to its base is ratio 2 find the area of triangle
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Answer :-
let ABC įß any traingle and AD įß altitude...
AB=BC ...
Let AB, BC be a..
let AD=h
Base =2 ..
perimeter = b+a+a=32 cm
12 +2a=32cm
2a=32-12
2a=20
a=10...
By Pythagoras theorem.... In traingle ADB
h²+b²=10²
h²=100-64
h²=64
h=8
Area of traingle = ½× base ×height
½×12×8
=48cm² Answer
Anonymous:
nice sistu
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