Question

find the zero of the polynomial x^2-5x+4​

Answer 1

Answer:

$x { }^{2} - 5x + 4 \\ (x {}^{2} -4x) - (x + 4) \\ x(x - 4) - 1(x - 4) \\ (x - 4)(x - 1) \\ x = 4 \: \\ x = 1 \\ so \: zeroes \: are \: \: (4 \: and \: 1)$

Answer 2

Answer:

x^2-4x-1x+4

x(x-4)-1(x-4)

(x-1)(x-4)

x=1,4