Question

Find the zero of the polynomial x2+2x–8.​

Answer 1

Answer: 2, -4

Step-by-step explanation:

$x^{2} +2x-8=0\\x^{2} +4x-2x-8=0\\x(x+4)-2(x+4)=0\\(x-2)(x+4)=0\\x=2\\or\\x=-4$

2 and -4 are the zeroes of the the given polynomial.

Answer 2

Answer:

x²+2x-8

x²-2x+4x-8 = 0

x(x-2)+4(x-2) = 0

(x+4)(x-2) = 0

Either (x+4) = 0 or (x-2) = 0

x = -4 or 2

Since ,it's a quadratic ,it will have 2 zeroes...

They r -4 and 2